A cannon on a level plane is aimed at an angle θ above the horizontal and a shell is fired with a muzzle velocity v₀ towards a vertical cliff a distance D away, Then the height from the bottom at which the shell strikes the side walls of the cliff is

• A

  $\mathrm{Dsin}\mathrm{\theta }-\frac{{\mathrm{gD}}^2}{2{{\mathrm{v}}_0}^2{\sin }^2\mathrm{\theta }}$

• B

  $\mathrm{Dcos}\mathrm{\theta }-\frac{{\mathrm{gD}}^2}{2{\mathrm{v}}_0^2{\cos }^2\mathrm{\theta }}$

• C

  $\mathrm{Dtan}\mathrm{\theta }-\frac{{\mathrm{gD}}^2}{2{\mathrm{v}}_0^2{\cos }^2\mathrm{\theta }}$

• D

  $\mathrm{Dtan}\mathrm{\theta }-\frac{{\mathrm{gD}}^2}{2{{\mathrm{v}}_0}^2{\sin }^2\mathrm{\theta }}$