A cannon shell moving along a straight line bursts into two parts. Just after the burst one part moves with momentum 40 Ns making an angle 300 with the original line of motion. The minimum momentum of the other part of shell just after the burst is
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a
0 Ns
b
10 N s
c
20 N s
d
17.32 N s
answer is C.
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Detailed Solution
As shown in the figure, the components of momentum of one shell along initial direction and perpendicular to initial direction are P1x = 20 3 Ns and P1y = 20 NsFor momentum of the system to be zeroiny-direction, P2y must be 20Ns. 2nd part of shell may or may not have momentum in x-direction∴P2min=20Ns
A cannon shell moving along a straight line bursts into two parts. Just after the burst one part moves with momentum 40 Ns making an angle 300 with the original line of motion. The minimum momentum of the other part of shell just after the burst is