First slide

Law of conservation of momentum and it's applications

Question

A cannon shell moving along a straight line bursts into two parts. Just after the burst one part moves with momentum 40 Ns making an angle $30^{0}$ with the original line of motion. The minimum momentum of the other part of shell just after the burst is

Moderate

A

0 Ns
B

10 N s
C

20 N s
D

17.32 N s

Solution

As shown in the figure, the components of momentum of one shell along initial direction and perpendicular to initial direction are $P_{1 x}$ = 20 $\sqrt{3}$ Ns and $P_{1 y} = 20 N s$
For momentum of the system to be zeroiny-direction, $P_{2 y}$ must be 20Ns. $2^{n d}$ part of shell may or may not have momentum in x-direction
$∴ P_{2 \min} = 20 N s$

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