A cannon shell moving along a straight line bursts into two parts. Just after the burst one part moves with momentum $$40$$ Ns making an angle $$300$$ with the original line of motion. The minimum momentum of the other part of shell just after the burst is

Question

A cannon shell moving along a straight line bursts into two parts. Just after the burst one part moves with momentum $$40$$ Ns making an angle $$300$$ with the original line of motion. The minimum momentum of the other part of shell just after the burst is

Infinity Learn · Accepted Answer

As shown in the figure, the components of momentum of one shell along initial direction and perpendicular to initial direction are $$P1x$$ $$=$$ $$20$$ $$3$$ Ns and $$P1y$$ $$=$$ $$20$$ NsFor momentum of the system to be $$zeroiny-direction$$, $$P2y$$ must be $$20Ns$$. $$2nd$$ part of shell may or may not have momentum in $$x-direction$$∴$$P2min=20Ns$$

A cannon shell moving along a straight line bursts into two parts. Just after the burst one part moves with momentum 40 Ns making an angle $30^{0}$ with the original line of motion. The minimum momentum of the other part of shell just after the burst is

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A cannon shell moving along a straight line bursts into two parts. Just after the burst one part moves with momentum 40 Ns making an angle 300 with the original line of motion. The minimum momentum of the other part of shell just after the burst is

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Ready to Test Your Skills?

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A cannon shell moving along a straight line bursts into two parts. Just after the burst one part moves with momentum 40 Ns making an angle $30^{0}$ with the original line of motion. The minimum momentum of the other part of shell just after the burst is