Q.

The capacitance of an air capacitor is 15 μF the separation between the parallel plates is 6 mm. A copper plate of 3 mm thickness is introduced symmetrically between the plates. The capacitance now becomes

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a

5 μF

b

7.5 μF

c

22.5 μF

d

30 μF

answer is D.

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Detailed Solution

By using Cair=ε0Ad, Cmedium=ε0Ad−t+tKFor K=∞ Cmedium =ε0Ad−t⇒CmCa=dd−t⇒Cm15=66−3⇒Cm=30 μF
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The capacitance of an air capacitor is 15 μF the separation between the parallel plates is 6 mm. A copper plate of 3 mm thickness is introduced symmetrically between the plates. The capacitance now becomes