The capacitance of an air filled parallel plate capacitor is 10μμF. The separation between the plates is doubled and the space between the plates is then filled with wax giving the capacitance a new value of 40×10−12 farads. The dielectric constant of wax is

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12.0

10.0

8.0

4.2

answer is C.

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Detailed Solution

C1=ε0Ad and C2=Kε0A2d⇒C2C1=K2⇒40×10−1210×10−12=K2⇒K=8

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