Questions
The capacities of two conductors are and and their respective potentials are and . If they are connected by a thin wire, then the loss of energy will be given by
detailed solution
Correct option is C
Initial energy Ui=12C1V12+12C2V22, final energy Uf=12C1+C2V2 (Where V=C1V1+C2V2C1+C2) Hence energy loss ΔU=Ui−Uf = 12C1V12+12C2V22 - C1+C22C1V1+C2V2C1+C22 =C1C22C1+C2V1−V22Talk to our academic expert!
Similar Questions
A 600 pF capacitor is charged by a 200 V supply. It is then disconnected from the supply and is connected to another uncharged 600 pF capacitor. What is the common potential (in V) and energy lost (in J) after reconnection?
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