The capacities of two conductors are C1 and C2 and their respective potentials are V1 and V2 . If they are connected by a thin wire, then the loss of energy will be given by
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a
C1C2V1+V22C1+C2
b
C1C2V1−V22C1+C2
c
C1C2V1−V222C1+C2
d
C1+C2V1−V2C1+C2
answer is C.
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Detailed Solution
Initial energy Ui=12C1V12+12C2V22, final energy Uf=12C1+C2V2 (Where V=C1V1+C2V2C1+C2) Hence energy loss ΔU=Ui−Uf = 12C1V12+12C2V22 - C1+C22C1V1+C2V2C1+C22 =C1C22C1+C2V1−V22
The capacities of two conductors are C1 and C2 and their respective potentials are V1 and V2 . If they are connected by a thin wire, then the loss of energy will be given by