Questions
A capacitor of capacitance C0 is charged to a potential V0 and then isolated. A small capacitor C is then charged from C0, discharged and charged again; the process being repeated n times. Due to this, the potential of the larger capacitor is decreased to V. The value of C is
detailed solution
Correct option is B
Potential of larger capacitor after the first charging isV1=C0V0C+C0After second charging, potential isV2=C0V1C+C0=C0C+C02V0After nth charging, potential isVn=C0C+C0nV0But Vn=VSo C=C0V0V1/n−1Talk to our academic expert!
Similar Questions
The plates of parallel plate capacitor are charged upto 100 V. A 2 mm thick plate is inserted between the plates. Then to maintain the same potential difference, the distance between the plates is increased by 1.6 mm. The dielectric constant of the plate is
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