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A capacitor of capacitance C₁ = 4 $μ$ F is charged to V₁ = 80V and another capacitor of capacitance C = 6 $μ$ F is charged to V₂ = 30V. When they are connected together, the energy lost by the 4 $μ$ F capacitor is

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detailed solution

Correct option is A

V=C1V1+C2V2C1+C2=50 V ∴ Energy lost by 4μF capacitor =12C1V12−12C1V2=7.8 mJ

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A capacitor of capacitance C1 = 4 μF is charged to V1 = 80V and another capacitor of capacitance C = 6 μF is charged to V2 = 30V. When they are connected together, the energy lost by the 4 μF capacitor is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A capacitor of capacitance C₁ = 4 $μ$ F is charged to V₁ = 80V and another capacitor of capacitance C = 6 $μ$ F is charged to V₂ = 30V. When they are connected together, the energy lost by the 4 $μ$ F capacitor is