First slide
Motional EMF
Question

A capacitor of capacitance C = 0.015F is connected to parallel conducting rail and a conducting rod of mass m = 100g and length l = 1 m start to fall under gravity in vertical plane. A uniform magnetic field of 2 T exist in space directed perpendicular to rod as shown in figure. Find acceleration of rod.

Moderate
Solution

ε=BvLQ=BvLC I=dQdt=BLCdvdt

For motion of rail

mg-ILB=mdvdt mg-L2B2Cdvdt=mdvdt dvdt=mgm+B2L2C=6.25m/s2

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