A capacitor of capacitance C has charge Q. It is connected to an identical capacitor through a resistance. The heat produced in the resistance is
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a
Q22C
b
Q24C
c
Q28C
d
dependent on the value of the resistance
answer is C.
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Detailed Solution
As the capacitors are identical, each of them finally have charge Q/2. Initial energy of the system is E1=Q22C. Final energy of the system is Ef=2(Q/2)22C=Q24C. Heat produced = loss in energy =Ei=Ef=Q24C