A capacitor of capacitance C' has initial charge Q0 and connected to inductor 'L' as shown, at t = 0 switch S is pressed. The current through the inductor when energy in the capacitor is three times of the energy of the inductor is
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a
Q02LC
b
Q0LC
c
2Q0LC
d
4Q0LC
answer is A.
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Detailed Solution
∵ total energy =Q022CQ022C=Q22C+Li22=Q22C+3Q22CQ022C=4Q22C⇒Q=Q02 Current at that instant =Qωi=Q02ω=Q02LC