A capacitor of capacitance 2 μF is connected in the tank circuit of an oscillator oscillating with a frequency of 1 kHz. If the current flowing in the circuit is 2 mA, the voltage across the capacitor will be

Reactance of capacitor or capacitive reactance is given byXC=1ωC=12πfCwhere f is frequency of the alternating currentGiven, f=1 × 103 Hz, C = 2 × 10−6 F∴    XC=12×3.14×103×2×10−6=1034×3.14Hence, voltage across the capacitor isV=iXC=2×10−3×1034×3.14=0.16V