Capacitors and capacitance

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Question

The capacitor of capacitance $4 μ F$ and $6 μ F$ are connected in series. A potential difference of $500 v o l t s$ applied to the outer plates of the two capacitor system. Then the charge on each capacitor is numerically____ $μ C$ .

Moderate

Solution

$C_{e q} = \frac{C_{1} C_{2}}{C_{1} + C_{2}} = 2.4 μ F C h a r g e s f l o w n, Q = C V = = 2.4 \times 500 \times 10^{- 6} C = 1200 μ C$

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