A capacitor of capacitance $$1$$μF withstands a maximum voltage of $$6$$ kV, while another capacitor of capacitance $$2$$μF withstands a maximum voltage of $$4kV$$. If they are connected in series, the combination can withstand a maximum of

Question

A capacitor of capacitance $$1$$μF  withstands a maximum voltage of $$6$$ kV, while another capacitor of capacitance $$2$$μF  withstands a maximum voltage of $$4kV$$. If they are connected in series, the combination can withstand a maximum of

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$$Ceff=1$$×$$21+2$$ μ$$F=23$$μF Capacitor $$1$$ can store a maximum charge $$1$$μF × $$6kV$$ $$=$$ $$6mC$$ . Capacitor $$2$$ can store a maximum charge of $$2$$μF × $$4kV$$ $$=$$ $$8mC$$. Since they are in series the charge in each capacitor $$=$$ $$6mc$$∴        Ceff. $$Vmax=1$$μF × $$6kV$$ ⇒$$Vmax=9$$ kV

Capacitance

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A capacitor of capacitance $1 μF$ withstands a maximum voltage of 6 kV, while another capacitor of capacitance $2 μF$ withstands a maximum voltage of 4kV. If they are connected in series, the combination can withstand a maximum of

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Capacitance

Remember concepts with our Masterclasses.

A capacitor of capacitance 1μF withstands a maximum voltage of 6 kV, while another capacitor of capacitance 2μF withstands a maximum voltage of 4kV. If they are connected in series, the combination can withstand a maximum of

Ceff=1×21+2 μF=23μF Capacitor 1 can store a maximum charge 1μF × 6kV = 6mC . Capacitor 2 can store a maximum charge of 2μF × 4kV = 8mC. Since they are in series the charge in each capacitor = 6mc∴ Ceff. Vmax=1μF × 6kV ⇒Vmax=9 kV

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A capacitor of capacitance $1 μF$ withstands a maximum voltage of 6 kV, while another capacitor of capacitance $2 μF$ withstands a maximum voltage of 4kV. If they are connected in series, the combination can withstand a maximum of