First slide

Capacitance

Question

A capacitor of charge $100 μC, 2 μF$ is connected another uncharged capacitor of capacity $6 μ F$ then common potential of both the capacitors is

Moderate

A

50 V
B

25 V
C

12.5 V
D

10 V

Solution

$\frac{100 - Q}{2} = \frac{Q}{6} \Rightarrow 300 - 3 Q = Q$
$\Rightarrow 4 Q = 300$
$\Rightarrow Q = 75$
$∴ V = \frac{75}{6} = 12.5 V$

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