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Questions  

A capacitor is charged by a battery. The battery is removed and another identical uncharged capacitor is connected in parallel. The total electrostatic energy of resulting system

a
decreases by a factor of  2
b
remains the same
c
increases by a factor of  2
d
increases by a factor of  4

detailed solution

Correct option is A

When the capacitor is charged by a battery of potential V, then energy stored in the capacitor,Ui=12CV2                   . . . . (i) When the battery is removed and another  identical  uncharged capacitor is connected in parallel Common potential,V'=CVC+C=V2∴ Then the energy stored in the capacitor, Uf=12(2C)V22=14CV2                        . . . . (ii)∴ From eqns. (i) and (ii) Uf=Ui2that means the total electrostatic energy of resulting system will decreases by a factor of 2.

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