Q.

A capacitor is charged by using a battery which is then disconnected. A dielectric slab is then slipped between the plates, which results in

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a

Reduction of charge on the plates and increase of potential difference across the plates

b

Increase in the potential difference across the plate, reduction in stored energy, but no change in the charge on the plates

c

Decrease in the potential difference across the plates, reduction in the stored energy, but no change in the charge on the plates

d

None of the above

answer is C.

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Detailed Solution

Battery in disconnected so Q will be constant. As C ∝K, so with introduction of dielectric slab capacitance will increase. Using Q = CV, V will decrease and using U=Q22C, energy will decrease
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A capacitor is charged by using a battery which is then disconnected. A dielectric slab is then slipped between the plates, which results in