Q.
A capacitor is charged by using a battery which is then disconnected. A dielectric slab is then slipped between the plates, which results in
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a
Reduction of charge on the plates and increase of potential difference across the plates
b
Increase in the potential difference across the plate, reduction in stored energy, but no change in the charge on the plates
c
Decrease in the potential difference across the plates, reduction in the stored energy, but no change in the charge on the plates
d
None of the above
answer is C.
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Detailed Solution
Battery in disconnected so Q will be constant. As C ∝K, so with introduction of dielectric slab capacitance will increase. Using Q = CV, V will decrease and using U=Q22C, energy will decrease
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