Questions
Capacitor A is charged to a potential of 100 V and, capacitor B is charged to a potential of 75 V. What are the charges on A and B after key is closed Fig.
a
2503μC;5003μC
b
2504μC;2503μC
c
5004μC;5003μC
d
12504μC;12503μC
detailed solution
Correct option is A
qA=5×100=500μCqB=10×75=750μCNet charge =750μC−500μC=250μC(∵Negative plate of A is connected to the positive plate of B)Common potential, V=2505+10=25015voltNow, qA′=C1V=5×25015=2503μCand qB′=C2V=10×25015=5003μCTalk to our academic expert!
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