Questions
A capacitor is charged until its stored energy is 3 J and the charging battery is removed. Another uncharged capacitor is then connected across it and we find that the charge distributes equally. Final value of total energy stored in the electric fields is :
detailed solution
Correct option is D
Initial total energy = Q22C=3 JFinal stored energy = Q222C+Q222C=Q24C=1.5 JTalk to our academic expert!
Similar Questions
Two identical metal plates are given positive charges Q1 and Q2 (<Q1) respectively. If they are now brought close together to form a parallel plate capacitor with capacitance C, the potential difference between them is
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