First slide

electric current

Question

A capacitor of 10 μF is charged to a potential difference of 20 V. If it is discharged in 0.2 s, the average current during discharging is :

Easy

A

1 mA
B

2 mA
C

4 mA
D

0.5 mA

Solution

$I_{av} = \frac{∆ q}{∆ t} = \frac{C ∆ V}{∆ t} = \frac{(10 x 10^{- 6}) (20)}{0.2} = 10^{- 3} A = 1 mA$

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