A capacitor of 10μF and an inductor of 1 H are joined in series. An ac of 50 Hz is applied to this combination. What is the impedance of the combination?

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5π2-5πΩ

10210-π2πΩ

10π2-5πΩ

510-π2πΩ

answer is B.

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Detailed Solution

Here,XL=ωL=2πfL=2π×50×1=100 πΩ XL=ωC=12πfC=12π×50×10×10-6=103πΩSo, X=XL-XC=100π-103π=102π2-10πΩ

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