A capacitor of 10 micro Farad and an inductor of 1H are joined in series. An ac of 50Hz is applied to this combination. What is the impedance of the combination?

Hence XL=ωL=2π/L=2π×50×1=100πΩ XC=1ωC=12πfC=12π×50×10×10−6=103πΩ So, X=XL−XC=100π−103π=102[π2−10π]Ω Z+R2+X2=|X|=102[10−9.86π]Ω i.e. Z=14πΩ=4.47Ω