A capacitor when filled with a dielectric K = 3 has charge Q0, voltage V0 and field E0. If the dielectric is replaced with another one having K = 9 the new values of charge, voltage and field will be respectively
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a
3Q0, 3V0, 3E0
b
Q0, 3V0, 3E0
c
Q0, V03, 3E0
d
Q0, V03, E03
answer is D.
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Detailed Solution
When there is no battery, charge remains same while potential difference and electric field decreases i.e. Q′=Q0,V′=V0×39=V03 and E′=E0×39=E03