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Q.

A capacitor when filled with a dielectric K = 3 has charge Q0, voltage V0 and field E0. If the dielectric is replaced with another one having K = 9 the new values of charge, voltage and field will be respectively

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a

3Q0, 3V0, 3E0

b

Q0, 3V0, 3E0

c

Q0, V03, 3E0

d

Q0, V03, E03

answer is D.

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Detailed Solution

When there is no battery, charge remains same while potential difference and electric field decreases i.e. Q′=Q0,V′=V0×39=V03 and E′=E0×39=E03

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