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The capacitors $C_{1}, C_{2} a n d C_{3}$ are uncharged initially and connected to A, B and C with potentials $V_{1}, V_{2} a n d V_{3}$ respectively. The potential of the junction D is :

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V1 + V2 + V33

C1V1 + C2V2 + C3V3C1 + C2 + C3

V1 + V2 + V3 C1C2C3C1 + C2 + C3

C1 + C2 + C3 V1 + V2 + V3V1V2V31/3

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detailed solution

Correct option is B

From conservation of chargeVA−VDC1=VD−VBC2+VD−VCC3V1C1+V2C2+VCC3=VDC2+C2+C3VD=C1V1+C2V2+C3V3C1+C2+C3

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The capacitors C1, C2 and C3 are uncharged initially and connected to A, B and C with potentials V1, V2 and V3respectively. The potential of the junction D is :

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The capacitors $C_{1}, C_{2} a n d C_{3}$ are uncharged initially and connected to A, B and C with potentials $V_{1}, V_{2} a n d V_{3}$ respectively. The potential of the junction D is :