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Q.

The capacity of a parallel plate capacitor with no dielectric substance but with a separation of 0.4 cm is 2 μ F. The separation is reduced to half and it is filled with a dielectric substance of value 2.8. The final capacity of the capacitor is

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a

11.2μF

b

15.6μF

c

19.2μF

d

22.4μF

answer is A.

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Detailed Solution

C=ε0KAd⇒C1C2=K1K2×d2d12C2=12.8×(0.4/2)(0.4)⇒C2=11.2μF
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