The capacity of a parallel plate condenser is C. If a dielectric of relative permittivity K and thickness equal to one-fourth of the plate separation is placed between the plates, then its capacity becomes C'. The value of C'/C will be

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4K3K+1

5K4K+1

2KK+1

K2(K+1)

answer is A.

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Detailed Solution

C=ε0Adand C′=ε0Ad−d41−1K=4ε0A3d+(d/K) =4ε0AKd(3K+1)=4KC(3K+1)

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