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Q.

The capacity of a parallel plate condenser is C. If a dielectric of relative permittivity K and thickness equal to one-fourth of the plate separation is placed between the plates, then its capacity becomes C'. The value of C'/C will be

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a

4K3K+1

b

5K4K+1

c

2KK+1

d

K2(K+1)

answer is A.

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Detailed Solution

C=ε0Adand  C′=ε0Ad−d41−1K=4ε0A3d+(d/K)          =4ε0AKd(3K+1)=4KC(3K+1)
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