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Q.

The capacity of a parallel plate condenser is 10 μF without dielectric. Dielectric of constant 2 is used to fill half the distance between the plates, the new capacitance in μF is

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a

10

b

20

c

15

d

13.33

answer is D.

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Detailed Solution

C=Aε0d=10μFC1=Aε0d−t+tk=Aε0d−d2+d2k=Aε0d21+12=43⋅Aε0d∴C1=43×10=13.33μF
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