A capillary tube is immersed vertically in liquid such that the capillary rise is ‘x’. This arrangement is taken in to a mine of ‘d’ depth. If height of rise is y. If R is radius of the of the earth, then depth of the mine in terms of R,x,y is

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R(y−xx)

R(y−xy)

R(xy−x)

R(yy−x)

answer is B.

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Detailed Solution

hrdg2cosθ=T hg=constant g at depth= g(1−dR)h2h1=g1g2 yx=gg1-dR 1-dR=xy 1-xy=dR d=y-xyR

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