A capillary tube is immersed vertically in liquid such that the capillary rise is ‘x’. This arrangement is taken in to a mine of ‘d’ depth. If height of rise is y. If R is radius of the of the earth, then depth of the mine in terms of R,x,y is
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a
R(y−xx)
b
R(y−xy)
c
R(xy−x)
d
R(yy−x)
answer is B.
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Detailed Solution
hrdg2cosθ=T hg=constant g at depth= g(1−dR)h2h1=g1g2 yx=gg1-dR 1-dR=xy 1-xy=dR d=y-xyR