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Q.

A car accelerates from rest at a constant rate of 2 ms-2 for some time. Then it retards at a constant rate of 4 ms-2 and comes to rest. It remains in motion for 6 s.

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a

Its maximum speed is 8 ms-1

b

Its maximum speed is 6 ms-1

c

It travelled a total distance of 24 m.

d

It travelled a total distance of 18 m.

answer is A.

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Detailed Solution

a1=2ms−2,a2=−4ms−2v0=a1t1=2t1,v0=a2t2=4t2t1+t2=6⇒v02+v04=6 ⇒v0=8ms−1Total distance travelledS=AC+CB=12v0t1+12v0t2=12×8×6=24m
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