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A car going due North at 10 $\sqrt{2}$ ${ms}^{- 1}$ turns right through an angle of $90^{0}$ without changing speed. The change in velocity of car is

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20 ms-1 in South-East direction

202 ms-1in South-East direction

20 ms-1North-East direction

20 ms-1 in North-West direction

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detailed solution

Correct option is

Initial velocity is vi = 102j^Final velocity is ∆v = vf-vi =102i-102j^∴ The change in velocity is ∆v = vf-vi = 102 i-102j^∴ |∆v| = (102)2+(102)2 = 400 = 20 ms-1 in South-East direction

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A car going due North at 102ms-1 turns right through an angle of 900 without changing speed. The change in velocity of car is

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A car going due North at 10 $\sqrt{2}$ ${ms}^{- 1}$ turns right through an angle of $90^{0}$ without changing speed. The change in velocity of car is