A  car going due North at 102ms-1 turns right through an angle of 900 without changing speed. The change in velocity of car is

Initial velocity is vi = 102j^Final velocity is ∆v = vf-vi =102i-102j^∴ The change in velocity is  ∆v = vf-vi = 102 i-102j^∴ |∆v| = (102)2+(102)2 = 400                    = 20 ms-1  in South-East direction