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A car of mass 400kg moving with constant acceleration covers distance between two points 60m apart in 6s. Its speed as it passes second point is 15ms−1. The kinetic energy of car at the first point is ______kJ

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answer is 5.

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Detailed Solution

VB2−VA=2as225−VA2=120a→1VB=VA+at15=Va+6aa=15−Va6→22 in 1225−VA2=120×15−VA6225−VA2=300−20VAVA2−20VA+75=0VA2−5VA-15=0VA=5ms−1 VB=15ms−1KEA=12mVA2=12×400×25=5000JKEA=5kJ

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