A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless road. If the banking angle is 450, the speed of the car is [CBSE AIPMT 2012]

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20 ms-1

30 ms-1

5 ms-1

10 ms-1

answer is B.

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Detailed Solution

The angle of banking tanθ=v2rgGiven, θ=45°,r=90 m and g=10 ms-2tan45°=v290×10⇒ v=90×10×tan45°Speed of car, v=30 ms-1

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