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Q.

A car of mass 1000 kg is taking a turn along a circular horizontal unbanked road of mean radius 100 m with permissible speed VP. Coefficient of static friction between the types and road surface is 0.4. When the car is taking the same turn with a speed VP/2, the resultant frictional force acting on the tyres will be

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a

1000 N

b

500 N

c

1500 N

d

750 N

answer is A.

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Detailed Solution

VP=μgR=0.4×10×100 ms=20 mswhen V=VP2, frictional force will be f=mV2R=1000×102100N=1000 N
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A car of mass 1000 kg is taking a turn along a circular horizontal unbanked road of mean radius 100 m with permissible speed VP. Coefficient of static friction between the types and road surface is 0.4. When the car is taking the same turn with a speed VP/2, the resultant frictional force acting on the tyres will be