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Q.

A car of mass 500kg(including the mass of a block) is moving on a smooth road with velocity 1.0ms-1 along positive x-axis. Now a block of mass 25kg is thrown outside with absolute velocity of 20 ms-1 along positive z-axis. The new velocity of the car is (ms-1)

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a

10 i^ +20 k^

b

10 i^ -20 k^

c

2019i^-2019k^

d

10i^-2019k^

answer is C.

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Detailed Solution

P→i=P→f, initial momentum = final momentum, from conservation prinicple of linear momentum(mcar+blockv)initial={(mv )block +(mremainingv )car}final∴(500)(1)(i^)=(25)(20k^)+475v→∴final velocity of car is v→=[(2019i^)−(2019k^)]m/s
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