A car of mass m starts from rest and acquires a velocity along east v=vi^(v>0) in two seconds.Assuming the car moves with uniform acceleration, the force exerted on the car is

Given, mass of the car = mAs car starts from rest, u = 0Velocity acquired along east, v=vi^Duration, t = 2 sFrom first equation of motion,v=u+at⇒vi^=0+a×2⇒a=v2i^Force, F=ma=mv2i^Hence, force acting on the car is  mv2 towards east due to friction on the tires exerted by the road.