First slide

Instantaneous acceleration

Question

A car of mass m, travelling at speed v, stops in time t when maximum braking force is applied. Assuming the braking force is same for both cases. What time would be required to sop a car of mass 2 m travelling at speed v?

Easy

A

$\frac{1}{2} t$
B

t
C

$\sqrt{2} t$
D

2 t

Solution

Let the acceleration of first car be a. Then acceleration of second car is.
For first car, 0 = v-at or t = $\frac{v}{a}$
For second car, 0 = v- $\frac{a}{2} t^{'} or t^{'} = \frac{2 v}{a} = 2 t$

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