A car moves from X to Y with a uniform speed vu and returns to Y with a uniform speed vd. The average speed for this round trip is
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a
2vdvuvd+vu
b
vuvd
c
vdvuvd+vu
d
vu+vd2
answer is A.
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Detailed Solution
we defineAverage speed = Distance travelledTime taken = dTLet t1 and t2 be times taken by the car to go from X to Y and then from Y to X respectivelyThen, t1+t2 = [XYvu]+[XYvd] = XY(vu+vdvuvd)Total distance travelled d = XY +XY = 2XYTherefore, average speed of the car for this round trip isvav = 2XYXY(vu+vdvuvd) or vav = 2vuvdvu+vd