Q.
A car moving along a straight highway with speed of 126 km/hr is brought to stop with in a distance of 200m. What is the retardation of the car
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a
3.06 m/s2
b
4 m/s2
c
5.06 m/s2
d
6 m/s2
answer is A.
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Detailed Solution
given initial velocity of car =u=126 km/hr⇒126×518m/s2⇒35 m/s2 The car finally comes to rest so V=0 From kinematics equation v2−u2=2asacceleration=a=v2−u22sa=02−3522×200a=−3.06m/s2
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