Q.

A car moving along a straight highway with speed of 126 km/hr is brought to stop with in a distance of 200m. What is the retardation of the car

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a

3.06 m/s2

b

4 m/s2

c

5.06 m/s2

d

6 m/s2

answer is A.

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Detailed Solution

given initial velocity of car =u=126 km/hr⇒126×518m/s2⇒35 m/s2 The car finally comes to rest so V=0   From kinematics equation v2−u2=2asacceleration=a=v2−u22sa=02−3522×200a=−3.06m/s2
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