A car is moving along a straight horizontal road with a speed u0. If the coefficient of friction between the tyres and the road is μ, the shortest distance in which the car can be stopped is
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a
u∘22μg
b
u0μg
c
u0μg2
d
u0μ
answer is A.
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Detailed Solution
Retarding force F=μR=μmg∴a=μgNow from equation of motion v2=u2−2as⇒0=u2−2as⇒s=u22a=u22μg∴s=u022μg