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A car is moving along a straight horizontal road with a speed $u_{0}$ . If the coefficient of friction between the tyres and the road is $μ$ , the shortest distance in which the car can be stopped is

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u∘22μg

u0μg

u0μg2

u0μ

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detailed solution

Correct option is A

Retarding force F=μR=μmg∴a=μgNow from equation of motion v2=u2−2as⇒0=u2−2as⇒s=u22a=u22μg∴s=u022μg

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