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Q.

A car is moving at a certain speed. The minimum distance over which it can be stopped is x. If the speed of the car is doubled, what will be the minimum distance over which the car can be stopped for the same retardation?

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a

4x

b

2x

c

x/2

d

x/4

answer is A.

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Detailed Solution

Let a be the maximum retardation the brakes of the car can produce. Then 2ax=v2. If v is doubled to 2v, then the minimum distance x is given by 2ax∗=(2v)2=4v2. Thus, x∗=4x.
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