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Q.

A car is moving on a straight horizontal road with a speed v. If the coefficient of friction between the tires and the road is μ, the shortest distance in which the car can be stopped is

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a

V2/2μg

b

v2/μg

c

(v/μg)2

d

v2/μ

answer is A.

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Detailed Solution

Initial K.E. of car =12mv2  work done against friction =μmgs Applying work energy theoremy, we have μmgs=12mv2  or  s=v2/(2μg)
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