A car is moving on a straight horizontal road with a speed v. If the coefficient of friction between the tires and the road is μ, the shortest distance in which the car can be stopped is
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a
V2/2μg
b
v2/μg
c
(v/μg)2
d
v2/μ
answer is A.
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Detailed Solution
Initial K.E. of car =12mv2 work done against friction =μmgs Applying work energy theoremy, we have μmgs=12mv2 or s=v2/(2μg)