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Questions  

 A car is moving on a straight horizontal road with a speed v. If the coefficient of friction between the tires and the road is μ, the shortest distance in which the car can be stopped is

a
V2/2μg
b
v2/μg
c
(v/μg)2
d
v2/μ

detailed solution

Correct option is A

Initial K.E. of car =12mv2  work done against friction =μmgs Applying work energy theoremy, we have μmgs=12mv2  or  s=v2/(2μg)

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The curved portions are smooth and horizontal surface is rough. The block is released from P. At what distance from A, it will stop (if μ = 0.8)?


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