A car moving on a straight road covers 25th of the total distance with speed'v1' and covers35th remaining distance with speed "v2" then average speed of car is
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a
12v1v2
b
v1+v22
c
2v1v2v1+v2
d
5v1v23v1+2v2
answer is D.
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Detailed Solution
Let the total distance is ‘S’ A car covers 25th of the total distance with v1 speed in time t1 35th of the total distance with v2 speed in time t2speed=distancetime time=distancespeed t1=25Sv1=2S5v1; t2=3S5v2 Average speed =Vav=total distancetotal time substitute,Vav=St1+t2 Vav=S2S5v1+3S5v2 Vav=SS52v1+3v2 Vav=52v2+3v1v1v2 Average speed =5v1v23v1+2v2