A car is moving towards check post with velocity of 54 kmh-1. When the car is at a distance of 400 m from the check post, the driver applies brakes which causes a deceleration of 0.3 ms-2. Find the distance (in meter) of car from the check post for 2 minutes after applying the brakes.
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answer is 25.
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Detailed Solution
Here, u=54×518=15ms−1a=−0.3ms−2∵ v=u+ator 0=15−0.3t0∴ t0=50sAfter 50 s, car permanently comes to rest. ∴s=u+v2t=15+02×50=375mThus, the distance of car from the check post is(400−375)m=25m