First slide

Different question variety formed

Question

A car moving with a speed of 50 km/h, can be stopped by brakes after at least 6 m. If the same car is moving at a speed of 100 km/h, the minimum stopping distance is :

Moderate

A

12 m
B

18 m
C

24 m
D

6m

Solution

Stopping distance is proportional to square of the vehicle speed $(s = \frac{u^{2}}{2 a})$ .
Hence for different vehicle speed and same deceleration, stopping distance $s' = s \cdot {(\frac{u'}{u})}^{2} = 6 \times {(\frac{100}{50})}^{2} m = 24 m$ .

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