A car moving with a speed of 50 km/hr can be stopped by brakes after at least 6 m. If the same car is moving at a speed of 100 km/hr the minimum stopping distance is

equation of motion is v2=u2+2aS  here v=final velocity;  u=initial velocity;  a=acceleration;  s=displacement acceleration =a=v2−u22S both cases have final velocity =0; acceleration is constant or same case1   →       u=50;      a=02−5022×6 case2   →        u=100;    a=02−10022×S equate acceleration of both cases ⇒02−5022×6=02−10022×S ⇒S=4×6=24m=minimum stopping distance