First slide

The 3 equation for uniform acc

Question

A car moving with a speed of 50 km/hr can be stopped by brakes after at least 6 m. If the same car is moving at a speed of 100 km/hr the minimum stopping distance is

Moderate

A

12 m
B

18 m
C

24 m
D

6 m

Solution

Motion of the car is retarded motion using $v^{2}$ = $u^{2}$ - 2as we can write, 0 = $u^{2}$ - 2as ⇒ s = $u^{2}$ /2a ⇒ s
$u^{2}$ $α$ s
s/6 = ${(100 / 50)}^{2}$ ⇒ s = 24m

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