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Q.

A car moving with a speed of 50 km/hr can be stopped by brakes after at least 6 m. If the same car is moving at a speed of 100 km/hr the minimum stopping distance is

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a

12 m

b

18 m

c

24 m

d

6 m

answer is C.

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Detailed Solution

Motion of the car is retarded motion using v2 = u2 - 2as we can write, 0 = u2 - 2as ⇒ s = u2/2a ⇒ s u2α ss/6 = (100/50)2 ⇒ s = 24m
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