A car is moving with uniform acceleration along a straight line between two stops X and Y. Its speed at X and Y are 2 ms-1 and 14 ms-1, Then

(14)2=(2)2+2as∴2as=192 unitsAt mid point, v2=(2)2+2as2=4+1922=100∴ v=10 m/sXA:AY=1:3XA=14s and AY=34sv12=(2)2+2as4=4+1924=52v1=52≠5 m/s10=2+at1(v=u+at)∴t1=8a14=10+at2∴t2=4a or t1=2t2S1=(2t)+12at2= distance travelled in first halfS2=2(2t)+12a(2t)2S3=S2-S1= distance travelled in second half. We can see that,S1≠S32