A car moving with a velocity of 10 ms-1 can be stopped by the application of a constant force F in a distance of 20 m If the velocity of the car is 30 ms-1, it can be stopped by this force in
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answer is 4.
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Detailed Solution
s ∝u2. If u becomes 3 times, then s will become 9 times, i.e. 9 x 20 = 180 m