A car sounding a horn of frequency 1000 Hz passes an observer. The ratio of frequencies of the horn noted by the observer before and after passing of the car is 11 : 9. If the speed of sound is v, the speed of the car is
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a
110v
b
12v
c
15v
d
v
answer is A.
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Detailed Solution
nBefore=vv−vcn and nAfter=vv+vc.nnBeforenAfter=119=v+vcv−vc⇒vc⇒v10