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Q.

A car sounding a horn of frequency 1000 Hz passes an observer. The ratio of frequencies of the horn noted by the observer before and after passing of the car is 11 : 9. If the speed of sound is v, the speed of the car is

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a

110v

b

12v

c

15v

d

v

answer is A.

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Detailed Solution

nBefore=vv−vcn  and  nAfter=vv+vc.nnBeforenAfter=119=v+vcv−vc⇒vc⇒v10
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