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Q.

A car is standing 600m behind a bus which is also at rest. The two start moving at the same instant but with different forward acceleration. The bus has acceleration 3m/sec2  and the car has acceleration 6 m/sec2 .The car will catch up with the bus after a time of

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a

20sec

b

10sec

c

10 2 sec

d

5sec

answer is A.

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Detailed Solution

relative separation of car w.r.t bus=sCB UC  =UB  =0 m/S    ucb  =0m/srelative acceleration of car w.r.t bus aCB=6−3=3m/sec2SCB =UCB +12 aCB  t2⇒600=123t2     ⇒12003=t2   ⇒t=20s
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