A car is standing 600m behind a bus which is also at rest. The two start moving at the same instant but with different forward acceleration. The bus has acceleration 3m/sec2 and the car has acceleration 6 m/sec2 .The car will catch up with the bus after a time of
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a
20sec
b
10sec
c
10 2 sec
d
5sec
answer is A.
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Detailed Solution
relative separation of car w.r.t bus=sCB UC =UB =0 m/S ucb =0m/srelative acceleration of car w.r.t bus aCB=6−3=3m/sec2SCB =UCB +12 aCB t2⇒600=123t2 ⇒12003=t2 ⇒t=20s