First slide
Instantaneous acceleration
Question

A car starting from rest, travels with uniform acceleration x and then comes to rest with uniform retardation y. If the total time of travel is t sec, the maximum velocity of the car is

Moderate
Solution

In accelerated motion,
V=u+xt1=0+xt1∴ V=xt1....(1)
When the car stops (after retardation)
0=v−yt−t1
where t =total time,
t1 = time of acceleration, and
t2 = time of retardation
∴v=yt−t1....(2)
From eqs. (1) and (2) 
xt1=yt−t1=yt−yt1
Solving, we get t1=yt/(x+y)
From eq,(1), v=xyt(x+y)

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