A car starting from rest, travels with uniform acceleration x and then comes to rest with uniform retardation y. If the total time of travel is t sec, the maximum velocity of the car is
In accelerated motion,
When the car stops (after retardation)
where t =total time,
t1 = time of acceleration, and
t2 = time of retardation
From eqs. (1) and (2)
Solving, we get
From eq,(1),